PHP日期函數date格式化UNIX時(shí)間的方法

　　文章主要介紹了PHP日期函數date格式化UNIX時(shí)間的方法,實(shí)例分析了php中date函數的使用技巧,需要的朋友可以參考下。

　　本文實(shí)例講述了PHP日期函數date格式化UNIX時(shí)間的方法。分享給大家供大家參考。具體分析如下：

　　日期函數可以根據指定的格式將一個(gè)unix時(shí)間格式化成想要的文本輸出

　　使用到函數語(yǔ)法如下

　　?

　　1

　　2

　　string date (string $Format);

　　string date (string $Format, int $Time);

　　下面是演示代碼

　　?

　　1

　　2

　　3

　　4

　　5

　　6

　　7

　　8

　　9

　　10

　　11

　　12

　　13

　　14

　　<?php

　　echo "When this page was loaded,\n";

　　echo 'It was then ', date ('r'), "\n";

　　echo 'The currend date was ', date ('F j, Y'), "\n";

　　echo 'The currend date was ', date ('M j, Y'), "\n";

　　echo 'The currend date was ', date ('m/d/y'), "\n";

　　echo 'The currend date was the ', date ('jS \o\f M, Y'), "\n";

　　echo 'The currend time was ', date ('g:i:s A T'), "\n";

　　echo 'The currend time was ', date ('H:i:s O'), "\n";

　　echo date ('Y');

　　date ('L')?(print ' is'):(print ' is not');

　　echo " a leap year\n";

　　echo time ('U'), " seconds had elapsed since January 1, 1970.\n";

　　?>

　　輸出結果如下

　　?

　　1

　　2

　　3

　　4

　　5

　　6

　　7

　　8

　　9

　　It was then Sat, 26 Dec 2009 07:09:51 +0000

　　The currend date was December 26, 2009

　　The currend date was Dec 26, 2009

　　The currend date was 12/26/09

　　The currend date was the 26th of Dec, 2009

　　The currend time was 7:09:51 AM GMT

　　The currend time was 07:09:51 +0000

　　2009 is not a leap year

　　1261811391 seconds had elapsed since January 1, 1970.

　　希望本文所述對大家的php程序設計有所幫助。

【PHP日期函數date格式化UNIX時(shí)間的方法】相關(guān)文章：

php的date()日期時(shí)間函數詳解11-12

php中date()日期時(shí)間函數使用方法11-11

PHP中date函數常用時(shí)間處理方法09-24

PHP時(shí)間和日期函數詳解10-17

PHP語(yǔ)言date函數應用07-22

PHP時(shí)間和日期函數怎么操作08-06

PHP獲取當前日期和時(shí)間及格式化方法參數10-07

php格式化時(shí)間戳的方法技巧10-28

PHP時(shí)間轉換Unix時(shí)間戳代碼08-19